B(b+4)=2b^2-32

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Solution for B(b+4)=2b^2-32 equation: 


Simplifying
B(b + 4) = 2b2 + -32

Reorder the terms:
B(4 + b) = 2b2 + -32
(4 * B + b * B) = 2b2 + -32
(4B + bB) = 2b2 + -32

Reorder the terms:
4B + bB = -32 + 2b2

Solving
4B + bB = -32 + 2b2

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Reorder the terms:
32 + 4B + bB + -2b2 = -32 + 2b2 + 32 + -2b2

Reorder the terms:
32 + 4B + bB + -2b2 = -32 + 32 + 2b2 + -2b2

Combine like terms: -32 + 32 = 0
32 + 4B + bB + -2b2 = 0 + 2b2 + -2b2
32 + 4B + bB + -2b2 = 2b2 + -2b2

Combine like terms: 2b2 + -2b2 = 0
32 + 4B + bB + -2b2 = 0

The solution to this equation could not be determined.

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